Plurals, If Statement Python

So many questions.. At the moment my code is calculating the cost, number of adults and children. If the user only inputs 1 child I want it to print child, not children. serviceTy

Solution 1:

Use x if ... else y construction:

defchildren_str(number):
    return"{} {}".format(number, 'child'if number == 1else'children')

for i inrange(3):
    print children_str(i)

Output:

0 children
1 child
2 children

you can generalize this function:

defpl(number, singular, plural=None):
    if plural == None:
        plural = singular + 's'return"{} {}".format(number, singular if number == 1else plural)

print (pl(1, 'child', 'children')) # 1 adultprint (pl(2, 'child', 'children')) # 2 childrenprint (pl(1, 'adult', 'adults')) # 1 adultprint (pl(2, 'adult')) # 2 adultsprint (pl(1, 'adult')) # 1 adultprint (pl(5, 'adult', 'adults')) # 5 adults

Solution 2:

If you want the plural and singular to be more general you may consider to use inflect, an python package

Then the conversion will looks like this:

import inflect

conversion_engine = inflect.engine()

defmain():

    for count inrange(4):
        print format_plural_singular("child",count)
        print format_plural_singular("adult",count)
        printdefformat_plural_singular(noun,quantity):
    return conversion_engine.plural_noun(noun,quantity)

Solution 3:

You can write the print statement like this:

print("That is " + formatCurrency(rare) + " for rare choice for " + str(noAdult) +
     (" adult"if noAdult==1else" adults") + " and " + str(noChild) +
     (" child"if noChild==1else" children") + ". Enjoy!")

Solution 4:

defpluralize(singular, plural):
    deffn(num):
        return"{} {}".format(num, singular if num==1else plural)
    return fn

children = pluralize("child",  "children")
adults   = pluralize("adult",  "adults")
seniors  = pluralize("senior", "seniors")

then

children(0)    # =>  "0 children"
children(1)    # =>  "1 child"
children(2)    # =>  "2 children"

and

def participants(num_seniors, num_adults, num_children):
    items = [
        (num_seniors,  seniors),
        (num_adults,   adults),
        (num_children, children)
    ]
    items = [fn(n) for n,fn in items if n >0]

    # joinlast pair of items with "and"
    items[-2:] = [" and ".join(items[-2:])]
    # joinall preceding items with ","
    return ", ".join(items)

participants(1, 2, 1)  # => "1 senior, 2 adults and 1 child"
participants(0, 1, 4)  # => "1 adult and 4 children"

Solution 5:

I came here looking for a very basic solution that followed a simple rule to add s if the count is more than 1. You can use Python's f-string form to do a simple inline if-statement in the f-string.

print(f"That is {formatCurrency(rare)} for rare choice for {noAdult} 
        adult{'s'if noAdult != 1else''} and {noChild}
        child{'ren'if noChild != 1else''}. Enjoy!"
)