Query To Fetch Highest Rated Movie With Mimimum 5 People Rated

I want to fetch name of movie with maximum rated movie with minimum 5 people rated in django. My code : model.py class Movie(models.Model): id = models.AutoField(primary_key=Tr

Solution 1:

I propose that you make some changes to your model. Normally ForeignKeys do not end with an id suffix, since Django will add a "twin field" with an _id suffix that stores the value of the target field. Furthermore you probably better make a ForeignKey to the user model. If you do not specify a primary key yourself, Django will automatically add an field named id that is an AutoField, hendce there is no need to add that manually. Finally you do not need to store the vote_count in a field of the Movie, you can retrieve that by counting the number of related Rating objects:

from django.conf import settings

classMovie(models.Model):
    title = models.CharField(max_length=100)

classRating(models.Model):
    user = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete.models.CASCADE)
    movie = models.ForeignKey(Movie, on_delete=models.CASCADE)
    rating = models.IntegerField()

Then we can retrieve the highest rated movie with:

from django.db.models import Avg, Count

higest_rated = Movie.objects.annotate(
    rating=Avg('rating__rating'),
    votes=Count('rating')
).filter(votes__gte=5).order_by('-rating').first()

Here the votes__gte=5 will filter such that it will only obtain Movies with five or more votes, and we order by rating in descending order.

Solution 2:

I'd modify the model, moving out Rating entity related fields from Watchlist and Movie.

Add the "Rate" class, and then filter by two conditions:

1. Count(Rate for the exact Movie) > minimum threshold(e.g. 5)
2. AVG(rating score for the exact Movie) > minimum threshold(e.g. 5) or, if you need top-rated movies, use Order by as it described in that answer

In your case, you could use Count and Average with Watchlist.Rating field