Python Selenium: Waiting For One Element Or Another Element To Load

I'm using this code for waiting for an element to load: browser = webdriver.Chrome(executable_path=chromedriver,options=ChromeOpts, desired_capabilities=captain) wait = WebDriverW

Solution 1:

You can combine the two checks in a single wait() operation - by using a python's lambda expression, using the find_elements_*() methods glued together with an or:

element = wait.until(lambda x: x.find_elements_by_id("id1") or x.find_elements_by_css_selector("#id2"))[0]

You can use this approach even to get the element that is matched first - the [0] at the end. This solution works, as find_elements_*() returns a list of all matched elements, or an empty one if there aren't such (a boolean false). So if the first call doesn't find anything, the second is evaluated; that repeats until either of them finds a match, or the time runs out.

This approach gives the benefit the wait.until() will stop immediately after one of the two passes - e.g. speed.

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Versus a try-catch block - in it, the first condition has to fail (waited for up to X seconds, usually 10), for the second one even to be checked; so if the first is false, while the second true - the runtime/wait is going to be at least X seconds plus whatever time the second check takes. In the worst case, when both are false, you are in for 2X wait, versus X in combining the two. If you add other conditions, you are only increasing the factor.

Solution 2:

You can do this by using expected_conditions

from selenium.webdriver.supportimport expected_conditions

the full solution can be found here: Selenium Expected Conditions - possible to use 'or'?

Solution 3:

I got it buy using TRY/EXCEPT.

openbrowser = browser.get(url) #navigate to the page 
try: 
   wait.until(EC.presence_of_element_located((By.ID, id_stop))) 
except: 
   wait.until(EC.presence_of_element_located((By.ID, 'rf-footer')))
browser.execute_script("window.stop();")