Roughly Approximate The Width Of A String Of Text In Python?
How would one, using Python, approximate the font width of a given string of text? I am looking for a function with a prototype similar to: def getApproximateFontWidth(the_string,
Solution 1:
Below is my simple solution, which gets you on the order of 80% accuracy, perfect for my purposes. It only works for Arial and it assumes 12 pt font, but it's probably proportional to other fonts as well.
defgetApproximateArialStringWidth(st):
size = 0# in milinchesfor s in st:
if s in'lij|\' ': size += 37elif s in'![]fI.,:;/\\t': size += 50elif s in'`-(){}r"': size += 60elif s in'*^zcsJkvxy': size += 85elif s in'aebdhnopqug#$L+<>=?_~FZT' + string.digits: size += 95elif s in'BSPEAKVXY&UwNRCHD': size += 112elif s in'QGOMm%W@': size += 135else: size += 50return size * 6 / 1000.0# Convert to picas
And if you want to truncate a string, here it is:
deftruncateToApproximateArialWidth(st, width):
size = 0# 1000 = 1 inch
width = width * 1000 / 6# Convert from picas to miliinchesfor i, s inenumerate(st):
if s in'lij|\' ': size += 37elif s in'![]fI.,:;/\\t': size += 50elif s in'`-(){}r"': size += 60elif s in'*^zcsJkvxy': size += 85elif s in'aebdhnopqug#$L+<>=?_~FZT' + string.digits: size += 95elif s in'BSPEAKVXY&UwNRCHD': size += 112elif s in'QGOMm%W@': size += 135else: size += 50if size >= width:
return st[:i+1]
return st
Then the following:
>> width = 15>> print truncateToApproxArialWidth("the quick brown fox jumps over the lazy dog", width)
the quick brown fox jumps over the
>> print truncateToApproxArialWidth("THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG", width)
THE QUICK BROWN FOX JUMPS
When rendered, those strings are roughly the same width:
the quick brown fox jumps over the
THE QUICK BROWN FOX JUMPS
Solution 2:
You could render an image with the text using PIL and then determine the resulting image width.
Solution 3:
I have used a library that does this however it requires pygame: http://inside.catlin.edu/site/compsci/ics/python/graphics.py Look under sizeString
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