Comparing Two Dict In Python To Get The Maximum Value For Similar Key
I have these 2 dicts: a={'test1':90, 'test2':45, 'test3':67, 'test4':74} b={'test1':32, 'test2':45, 'test3':82, 'test4':100} how to extract the maximum value for the same ke
Solution 1:
You can try like this,
>>> a={"test1":90, "test2":45, "test3":67, "test4":74}
>>> b={"test1":32, "test2":45, "test3":82, "test4":100}
>>> c = { key:max(value,b[key]) for key, value in a.iteritems() }
>>> c
{'test1': 90, 'test3': 82, 'test2': 45, 'test4': 100}
Solution 2:
Try this:
>>> a={"test1":90, "test2":45, "test3":67, "test4":74}
>>> b={"test1":32, "test2":45, "test3":82, "test4":100}
>>> c={ k:max(a[k],b[k]) for k in a if b.get(k,'')}
{'test1': 90, 'test3': 82, 'test2': 45, 'test4': 100}
Solution 3:
Not the best, but still a variant:
from itertools import chain
a = {'test1':90, 'test2': 45, 'test3': 67, 'test4': 74}
b = {'test1':32, 'test2': 45, 'test3': 82, 'test4': 100, 'test5': 1}
c = dict(sorted(chain(a.items(), b.items()), key=lambda t: t[1]))
assert c == {'test1': 90, 'test2': 45, 'test3': 82, 'test4': 100, 'test5': 1}
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