How To Print Out Tags In Python

If I have a string such as this: text = 'They refuse to permit us.' txt = nltk.word_tokenize(text) With this if I print POS tags; nltk.pos_tag(txt) I get [('They','PRP'), ('ref

Solution 1:

You got a list of tuples, you should iterate through it to get only the second element of each tuple.

>>> tagged = nltk.pos_tag(txt)
>>> tags =  [ e[1] for e in tagged]
>>> tags
['PRP', 'VBP', 'TO', 'VB', 'PRP'] 

Solution 2:

Take a look at Unpacking a list / tuple of pairs into two lists / tuples

>>> from nltk import pos_tag, word_tokenize
>>> text = "They refuse to permit us.">>> tagged_text = pos_tag(word_tokenize(text))
>>> tokens, pos = zip(*tagged_text)
>>> pos
('PRP', 'VBP', 'TO', 'VB', 'PRP', '.')

Possibly at some point you will find the POS tagger is slow and you will need to do this (see Slow performance of POS tagging. Can I do some kind of pre-warming?):

>>>from nltk import pos_tag, word_tokenize>>>from nltk.tag import PerceptronTagger>>>tagger = PerceptronTagger()>>>text = "They refuse to permit us.">>>tagged_text = tagger.tag(word_tokenize(text))>>>tokens, pos = zip(*tagged_text)>>>pos
('PRP', 'VBP', 'TO', 'VB', 'PRP', '.')

Solution 3:

You can iterate like -

print [x[1] for x in nltk.pos_tag(txt)]