Python Execute() Takes Exactly 2 Arguments (3 Given)

I am trying to insert into the SQLite DataBase values with this code: con.Execute('''UPDATE tblPlayers SET p_Level = ? WHERE p_Username= ? ''', (PlayerLevel,PlayerUsername)) this

Solution 1:

Your Execute() method takes only two arguments, self and SQL. The self argument is supplied by Python to bound methods, so there is only room for the SQL argument:

def Execute(self,SQL):

but you called the bound method with an additional argument, not just the one SQL argument:

con.Execute('''UPDATE tblPlayers SET p_Level = ? WHERE p_Username= ? ''',
            (PlayerLevel,PlayerUsername))

The tuple value passed in, together with the auto-inserted self argument and the SQL argument makes three.

If you want to support SQL parameters, you'll need to accept those parameters:

def Execute(self, SQL, params=()):
    self.__connection.execute(SQL, params)
    self.__connection.commit()

Solution 2:

This line says you are inputting two arguments:

con.Execute('''UPDATE tblPlayers SET p_Level = ? WHERE p_Username= ? ''', (PlayerLevel,PlayerUsername))

Add those 2 arguments to the implicit self argument that's passed automatically with the instance, you now have 3 arguments.

Either keep to 1 argument when calling it or modify the definition of Execute to accomodate 1 more argument.